awk how to print line minus end characters
# Basic syntax:
awk '{print substr($0, 1, length($0)-#_characters)}' input_file
# Where #_characters is the number of characters you want to remove
# Example usage:
# Say your input_file has the line:
Id rather not end this line with garbage garbage
awk '{print substr($0, 1, length($0)-7)}' input_file # Would print:
--> Id rather not end this line with garbage
# Note, the general syntax for the awk substr() command is:
substr(field, start_character, number_characters_to_print_beyond_start)
# Note, tabs are treated as one character
Also in C++:
- bash float operations
- digitalocean redirect http to https nginx
- how to add multiple files in git
- open visual studio code from terminal ubuntu
- spotify ubuntu
- grep on mac os terminal
- kali linux
- delete local git repository command line creates by react
- how to install wordcloud in python
- check go is installed mac
- how to run pyinstaller generate application in linux
- ubuntu rename user login
- the current numpy installation fails to pass a sanity check due to a bug in the windows runtime
- list apt installed programs
- - Installation request for jenssegers/mongodb ^3.6 -> satisfiable by jenssegers/mongodb[v3.6.0, v3.6.1, v3.6.2, v3.6.3, v3.6.4]. - Conclusion: don't install laravel/framework v7.22.4
- ngrok run in background and get link
- bagisto
- linux scroll terminal
- raccourci tor browser sur ubuntu
- remove a folder from git tracking
- gestures in ubuntu
- see what is using a port ubuntu
- tigervnc install on centos 7 step by step
- flutter plugin installed but in flutter doctor it shows not installed