map java

import java.util.HashMap;
import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;


public class Main {
   public static void main(String[] args) {

      //La fameuse syntaxe en diamant de Java 7
      Map<Integer, String> hm = new HashMap<>();
      hm.put(10, "1");
      hm.put(20, "2");
      hm.put(30, "3");
      hm.put(40, "4");
      hm.put(50, "5");
      //Ceci va écraser la valeur 5
      hm.put(50, "6");
      
      System.out.println("Parcours de l'objet HashMap : ");
      Set<Entry<Integer, String>> setHm = hm.entrySet();
      Iterator<Entry<Integer, String>> it = setHm.iterator();
      while(it.hasNext()){
         Entry<Integer, String> e = it.next();
         System.out.println(e.getKey() + " : " + e.getValue());
      }
      
      System.out.println("Valeur pour la clé 8 : " + hm.get(8));
      
      Map<Integer, String> lhm = new LinkedHashMap<>();
      lhm.put(10, "1");
      lhm.put(20, "2");
      lhm.put(30, "3");
      lhm.put(40, "4");
      lhm.put(50, "5");
      
      System.out.println("Parcours de l'objet LinkedHashMap : ");      
      Set<Entry<Integer, String>> setLhm = lhm.entrySet();
      Iterator<Entry<Integer, String>> it2 = setLhm.iterator();
      while(it2.hasNext()){
         Entry<Integer, String> e = it2.next();
         System.out.println(e.getKey() + " : " + e.getValue());
      }
   }
}
The map() method creates a new array with the results of calling a provided function on every element in the calling array.