check if even or odd javascript

function isEven(n) {
   return n % 2 == 0;
}

function isOdd(n) {
   return Math.abs(n % 2) == 1;
}function evenOrOdd(num) { //for string length take string
  if (num % 2 == 0) {//and replace numm with string.length here
    return "even";
  } else {
    return "odd";
  }
}for(let count =0; count<=100;count++){
 count%2==0? console.log(`${count} is even`):console.log(`${count} is odd`);
 ;
}let isEven = (n) => !(n&1);