javascript reduce

JavaScript
const sum = array.reduce((accumulator, element) => {
  return accumulator + element;
}, 0);
// An example that will loop through an array adding
// each element to an accumulator and returning it
// The 0 at the end initializes accumulator to start at 0
// If array is [2, 4, 6], the returned value in sum
// will be 12 (0 + 2 + 4 + 6)

const product = array.reduce((accumulator, element) => {
  return accumulator * element;
}, 1);
// Multiply all elements in array and return the total
// Initialize accumulator to start at 1
// If array is [2, 4, 6], the returned value in product
// will be 48 (1 * 2 * 4 * 6)function reduce(array, func, seed) {
  let previousResult;
  if (seed === undefined) {
    previousResult = array[0];
    for (let i = 1; i < array.length; i++) {
      previousResult = func(previousResult, array[i], i, array);
    }
    console.log(previousResult);
  } else {
    previousResult = seed;
    each(array, function(e, i, a) {
      previousResult = func(previousResult, e, i, array);
    });
  }
  return previousResult;
};var array = [36, 25, 6, 15];

array.reduce(function(accumulator, currentValue) {
  return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82let nums = [1, 2, 3];

nums.reduce((curr, next) => curr + next);var objs = [
  {name: "Peter", age: 35},
  {name: "John", age: 27},
  {name: "Jake", age: 28}
];

objs.reduce(function(accumulator, currentValue) {
  return accumulator + currentValue.age;
}, 0); // 35 + 27 + 28 = 90function getArraySum(a){
    var total=0;
    for(var i in a) { 
        total += a[i];
    }
    return total;
}

var payChecks = [123,155,134, 205, 105]; 
var weeklyPay= getArraySum(payChecks); //sums up to 722
Source

Also in JavaScript: