javascript sum of array
const arr = [1, 2, 3, 4];
const sum = arr.reduce((a, b) => a + b, 0);
// sum = 10const sum = arr => arr.reduce((a, b) => a + b, 0);[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10console.log(
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
)
console.log(
[].reduce((a, b) => a + b, 0)
)const arrSum = arr => arr.reduce((a,b) => a + b, 0)arrSum = function(arr){ return arr.reduce(function(a,b){ return a + b }, 0);}
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