permutation javascript

JavaScript
function getArrayMutations(arr, perms = [], len = arr.length) {
  if (len === 1) perms.push(arr.slice(0))

  for (let i = 0; i < len; i++) {
    getArrayMutations(arr, perms, len - 1)

    len % 2 // parity dependent adjacent elements swap
      ? [arr[0], arr[len - 1]] = [arr[len - 1], arr[0]]
      : [arr[i], arr[len - 1]] = [arr[len - 1], arr[i]]
  }

  return perms
}const permutations = arr => {
  if (arr.length <= 2) return arr.length === 2 ? [arr, [arr[1], arr[0]]] : arr;
  return arr.reduce(
    (acc, item, i) =>
      acc.concat(
        permutations([...arr.slice(0, i), ...arr.slice(i + 1)]).map(val => [
          item,
          ...val,
        ])
      ),
    []
  );
};
Source

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