"this is a test string".split("").reverse().join("");
//"gnirts tset a si siht"
// Or
const reverse = str => [...str].reverse().join('');
// Or
const reverse = str => str.split('').reduce((rev, char)=> `${char}${rev}`, '');
// Or
const reverse = str => (str === '') ? '' : `${reverse(str.substr(1))}${str.charAt(0)}`;
// Example
reverse('hello world'); // 'dlrow olleh'function reverseString(str) {
// Step 1. Create an empty string that will host the new created string
var newString = "";
// Step 2. Create the FOR loop
/* The starting point of the loop will be (str.length - 1) which corresponds to the
last character of the string, "o"
As long as i is greater than or equals 0, the loop will go on
We decrement i after each iteration */
for (var i = str.length - 1; i >= 0; i--) {
newString += str[i]; // or newString = newString + str[i];
}
/* Here hello's length equals 5
For each iteration: i = str.length - 1 and newString = newString + str[i]
First iteration: i = 5 - 1 = 4, newString = "" + "o" = "o"
Second iteration: i = 4 - 1 = 3, newString = "o" + "l" = "ol"
Third iteration: i = 3 - 1 = 2, newString = "ol" + "l" = "oll"
Fourth iteration: i = 2 - 1 = 1, newString = "oll" + "e" = "olle"
Fifth iteration: i = 1 - 1 = 0, newString = "olle" + "h" = "olleh"
End of the FOR Loop*/
// Step 3. Return the reversed string
return newString; // "olleh"
}
reverseString('hello');function reverseString(str) {
// Step 1. Use the split() method to return a new array
var splitString = str.split(""); // var splitString = "hello".split("");
// ["h", "e", "l", "l", "o"]
// Step 2. Use the reverse() method to reverse the new created array
var reverseArray = splitString.reverse(); // var reverseArray = ["h", "e", "l", "l", "o"].reverse();
// ["o", "l", "l", "e", "h"]
// Step 3. Use the join() method to join all elements of the array into a string
var joinArray = reverseArray.join(""); // var joinArray = ["o", "l", "l", "e", "h"].join("");
// "olleh"
//Step 4. Return the reversed string
return joinArray; // "olleh"
}
reverseString("hello");function reverseString(str) {
if (str === "") // This is the terminal case that will end the recursion
return "";
else
return reverseString(str.substr(1)) + str.charAt(0);
/*
First Part of the recursion method
You need to remember that you won’t have just one call, you’ll have several nested calls
Each call: str === "?" reverseString(str.subst(1)) + str.charAt(0)
1st call – reverseString("Hello") will return reverseString("ello") + "h"
2nd call – reverseString("ello") will return reverseString("llo") + "e"
3rd call – reverseString("llo") will return reverseString("lo") + "l"
4th call – reverseString("lo") will return reverseString("o") + "l"
5th call – reverseString("o") will return reverseString("") + "o"
Second part of the recursion method
The method hits the if condition and the most highly nested call returns immediately
5th call will return reverseString("") + "o" = "o"
4th call will return reverseString("o") + "l" = "o" + "l"
3rd call will return reverseString("lo") + "l" = "o" + "l" + "l"
2nd call will return reverserString("llo") + "e" = "o" + "l" + "l" + "e"
1st call will return reverserString("ello") + "h" = "o" + "l" + "l" + "e" + "h"
*/
}
reverseString("hello");function reverseString(str) {
var newString = "";
for (var i = str.length - 1; i >= 0; i--) {
newString += str[i];
}
return newString;
}
reverseString('hello');function reverseString(str) {
return str;
}
reverseString("hello");