//you can use two functions depending of what you want to do:
let animals1 = ["dog", "cat", "mouse"]
delete animals1[1]
/*this deletes all the information inside "cat" but the element still exists
so now you'll have this:*/
console.log(animals1)//animals1 = ["dog", undefined, "mouse"]
//if you want to delete it completely, you have to use array.splice:
let animals2 = ["dog", "cat", "mouse"]
animals2.splice(1, 1)
/*the first number means the position from which you want to start to delete
and the second is how much elements will be deleted*/
console.log(animals2)//animals2 = ["dog", "mouse"]
/*Now you don't have undefined
If you did this:*/
let animals3 = ["dog", "cat", "mouse"]
animals3.splice(0, 2)//you'll have this:
console.log(animals3)//animals 3 = "mouse"
/*This happens because I put a 2 in the second parameter so it deleted
two elements from position 0
Try copying this code in your console and whatch*/var array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0];
var filtered = array.filter(function(value, index, arr){
return value > 5;
});
//array => [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
//filtered => [6, 7, 8, 9]